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return nvtab nval++;
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newname;
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The function addname returns the index of the item just added, or -1 if some error occurred
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SECTION 26
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The call to real 1oc grows the array to the new size, preserving the existing elements, and returns a pointer to it or NULL if there isn't enough memory Doubling the size in each r e a l 1oc keeps the expected cost of copying each element constant: if the array grew by just one element on each call, the performance could be 0 ( n 2 ) Since the address of the array may change when it is reallocated, the rest of the program must refer to elements of the array by subscripts not pointers Note that the code doesn't say
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nvtab nameval = (Nameval a) r e a l 1oc (nvtab nameval , (NVGROWnnvtab max) * s i zeof (Nameval )) ;
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[n this form if the reallocation were to fail, the original array would be lost We start with a very small initial value (NVINIT = 1)for the array size This forces the program to grow its arrays right away and thus ensures that this part of the program is exercised The initial size can be increased once the code goes into production use, though the cost of starting small is negligible The return value of r e a l l o c does not need to be cast to its final type because C promotes the void* automatically But C++ does not; there the cast is required One can argue about whether it is safer to cast (cleanliness, honesty) or not to cast (the cast can hide genuine errors) We chose to cast because it makes the program legal in both C and C++; the price is less error-checking from the C compiler, but that is offset by the extra checking available from using two compilers Deleting a name can be tricky because we must decide what to do with the resulting gap in the array If the order of elements does not matter, it is easiest to swap the last element into the hole If order is to be preserved however we must move the elements beyond the hole down by one position:
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/* delname: remove f i r s t matching nameval from nvtab in t del name(char *name)
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int i ; f o r (i = 0 ; i < nvtabnva1; i++) i f (strcmp(nvtab nameval [i name, name) == 0) { ] memmove(nvtab nameval +i nvtab nameval + i +l, , (nvtab nval- (i+l)) * s i z e o f (Nameval)) ; nvtab nval -- ; return 1;
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return 0 ;
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The call to memmove squeezes the array by moving the elements down one position; memmove is a standard library routine for copying arbitrary-sized blocks of memory The ANSI C standard defines two functions: memcpy, which is fast but might overwrite memory if source and destination overlap; and memmove, which might be slower but will always be correct The burden of choosing correctness over speed should not
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be placed upon the programmer; there should be only one function Pretend there is, and always use memmove We could replace the memmove call with the following loop: int j; f o r ( j = i ; j < nvtabnva1-1; j++) nvtab nameval [j] = nvtab nameval [j+l]; We prefer to use memmove because it avoids the easy-to-make mistake of copying the elements in the wrong order If we were inserting instead of deleting, the loop would need to count down, not up, to avoid overwriting elements By calling memmove we don't need to think it through each time An alternative to moving the elements of the array is to mark deleted elements as unused Then to add a new item, first search for an unused slot and grow the vector only if none is found In this example, an element can be marked as unused by setting its name field to NULL Arrays are the simplest way to group data; it's no accident that most languages provide efficient and convenient indexed arrays and represent strings as arrays of characters Arrays are easy to use, provide O( 1 ) access to any item, work well with binary search and quicksort, and have little space overhead For fixed-size data sets, which can even be constructed at compile time, or for guaranteed small collections of data, arrays are unbeatable But maintaining a changing set of values in an array can be expensive, so if the number of elements is unpredictable and potentially large, it may be better to use another data structure
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Exercise 2-5 In the code above, del name doesn't call real 1oc to return the memory freed by the deletion Is this worthwhile How would you decide whether to do so
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Exercise 2-6 Implement the necessary changes to addname and del name to delete items by marking deleted items as unused How isolated is the rest of the program from this change
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