const i n t M X O = 24 MAXCOL = 80; AR W in Java

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const i n t M X O = 24 MAXCOL = 80; AR W
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SECTION 15
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or f i n a l in Java:
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s t a t i c f i n a l in t MAXROW = 2 4 , MAXCOL = 80;
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C also has const values but they cannot be used as array bounds, so the enum statement remains the method of choice in C
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Use character constants, not integers The functions in <ctype h> or their equivalent should be used to test the properties of characters A test like this:
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depends completely on a particular character representation It's better to use
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i f (c >= 'A' && c <= '2')
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but that may not have the desired effect if the letters are not contiguous in the character set encoding or if the alphabet includes other letters Best is to use the library:
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i f (i supper (c))
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i f (Character isUpperCase(c))
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in Java A related issue is that the number 0 appears often in programs, in many contexts The compiler will convert the number into the appropriate type, but it helps the reader to understand the role of each 0 if the type is explicit For example, use (voi d*)O or NULL to represent a zero pointer in C, and ' \ 0 ' instead of 0 to represent the null byte at the end of a string In other words, don't write
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s t r = 0; name[i]=O; x = o ;
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but rather:
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s t r = NULL; name[il = ' \ 0 ' ; x = 00;
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We prefer to use different explicit constants, reserving 0 for a literal integer zero, because they indicate the use of the value and thus provide a bit of documentation In C++, however, 0 rather than NULL is the accepted notation for a null pointer Java solves the problem best by defining the keyword nu11 for an object reference that doesn't refer to anything
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STYLE
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CHAPTER I
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Use the language to calculate the size of an object Don't use an explicit size for any data type; use s i z e o f ( i n t ) instead of 2 or 4, for instance For similar reasons, sizeof(array[O]) may be better than s i z e o f ( i n t ) because it's one less thing to change if the type of the array changes The s i zeof operator is sometimes a convenient way to avoid inventing names for the numbers that determine array sizes For example if we write
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char buf [lo241 ; f g e t s ( b u f , s i zeof (buf)
s t d i n) ;
the buffer size is still a magic number, but it occurs only once, in the declaration It may not be worth inventing a name for the size of a local array, but it is definitely worth writing code that does not have to change if the size or type changes Java arrays have a 1 ength field that gives the number of elements:
char buf [I = new char [lo241 ; for ( i n t i = 0 ; i < b u f l e n g t h ; i + + )
There is no equivalent of l ength in C and C++, but for an array (not a pointer) whose declaration is visible, this macro computes the number of elements in the array:
# d e f i n e NELEMS(array) ( s i zeof (array) double dbuf [ I 0 0 1 ; f o r (i = 0 ; i < NELEMS(dbuf);
/ s i zeof ( a r r a y 101))
i++)
The array size is set in only one place; the rest of the code does not change if the size does There is no problem with multiple evaluation of the macro argument here, since there can be no side effects, and in fact the computation is done as the program is being compiled This is an appropriate use for a macro because it does something that a function cannot: compute the size of an array from its declaration