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In the next series of DataGrid examples, the following code will be assigned to the Page_Load method and the BindEmployees method:
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Private Sub Page_Load(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles MyBase.Load If Not IsPostBack() Then BindEmployees() End If End Sub Public Sub BindEmployees() Create employee list if it does not exist. If Session( Employees ) Is Nothing Then Dim a As New ArrayList() a.Add(New Employee(1, GlennLast , Glenn , 50000)) a.Add(New Employee(2, JoeLast , Joe , 42000)) a.Add(New Employee(3, MaryLast , Mary , 31000)) a.Add(New Employee(4, FrankLast , Frank , 36000)) a.Add(New Employee(5, AnneLast , Anne , 24000)) Session( Employees ) = a End If DataGrid1.DataSource = Session( Employees ) DataGrid1.DataBind() End Sub
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The code is using the Employee class that was used in the previous Repeater and DataList examples, and five Employee instances are added to an ArrayList. In this example, the DataGrid is placed on to the Web page. When the page is displayed (see Figure 6.11), the DataGrid created and rendered three columns. Notice that the employee ID (EID) of the employees has not been rendered, because the DataGrid is not looking for public fields; it s only looking for public properties. Assigning a Style to the DataGrid The DataGrid supports style elements, which allows the style to change without repeating the same code. For example, the Repeater control examples in this chapter had the same code for the ItemTemplate and the AlternatingItemTemplate. The only thing that was different was the style. The DataGrid solves the problem with these special style elements. The following is a list of style elements that are supported by the DataGrid. Figure 6.5 shows the style hierarchy.
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In addition to these styles, a quick way to assign a style is to right-click the DataGrid and then click Auto Format. The Auto Format window displays many options that allow the DataGrid to be quickly formatted. Professional 3 will be used in the following examples, as shown in Figure 6.11. Adding Columns to the DataGrid You can add columns to the DataGrid via HTML, code, or the Property Builder. The following types of columns may be added to the DataGrid: BoundColumn. A column that can be bound to a field in the data source. ButtonColumn. A column that contains a command button. This button can be used with the item on the current row (for example, Add or Delete). EditCommandColumn. A column that displays an Edit button until a row is being edited. When a row is being edited, Cancel and Update buttons will be placed in the column on the edited row. HyperLinkColumn. A column that displays a hyperlink button, which can be configured to provide a URL and a querystring that contains information about the current item. TemplateColumn. A column with the ability to be completely customized with templates. In the previous example, the employee ID column was missing. The following code adds the employee ID to the DataGrid.
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Private Sub DataGrid1_Init(ByVal sender As Object, _ ByVal e As System.EventArgs) _ Handles DataGrid1.Init Dim col As New BoundColumn() col.HeaderText = Employee ID DataGrid1.Columns.Add(col) End Sub
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It is important to add the column as early as possible in the DataGrid control s life cycle. Adding the column in the Init event method of the DataGrid means that the column will be available to work with ViewState and be assigned data. Although a bound column was used, a DataField could not be provided because the EID is a public variable instead of a property. Although this column will be displayed, there will not be any data.
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Figure 6.11 DataGrid rendered with default settings (left), and with Professional 3 style selected (right).
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An easy way to populate the data would be to add code to the DataGrid s ItemDataBound event method. This method executes every time that a row needs to be rendered. One problem is that this will execute on the header and footer rows, so a check needs to be done to verify that there is data available for a row before attempting to extract the EID. The following code will get the EID and populate column 0, which is the Employee ID column.
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Private Sub DataGrid1_ItemDataBound(ByVal sender As Object, _ ByVal e As System.Web.UI.WebControls.DataGridItemEventArgs) _ Handles DataGrid1.ItemDataBound If TypeOf e.Item.DataItem Is Employee Then Dim currentEmployee As Employee = _ CType(e.Item.DataItem, Employee) e.Item.Cells(0).Text = _ string.Format( {0:D3} ,currentEmployee.EID) End If End Sub