#include <string> in Java

Creation QR Code JIS X 0510 in Java #include <string>
#include <string>
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#include <iostream> int main() { string numerics( "0123456789" ); string name( "r2d2" ); string::size_type pos = namefind_first_of( numerics ); cout "found numeric at index: " pos "\telement is " name[pos] endl; }
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In this example, pos is set to a value of 1 (the elements of a string, remember, are indexed beginning at 0) However, this still does not do quite what we need We need to find all occurrences in sequence and not just the first occurrence We can do this by providing a second argument indicating the index position within the string to start our search Here is a rewrite of our search of "r2d2" It is still not quite right, however Do you see what is wrong
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#include <string> #include <iostream> int main() { string numerics( "0123456789" ); string name( "r2d2" ); string::size_type pos = 0; // something wrong with implementation! while (( pos = namefind_first_of( numerics, pos )) != string::npos ) cout "found numeric at index: " pos "\telement is " name[pos] endl; }
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pos begins the loop initialized to 0 The string is searched beginning at position 0 A match occurs at index 1 pos is assigned that value Because it is not equal to npos, the body of the loop is executed A second find_first_of() executes with pos set to 1 Oops! Position 1 matches a second, third, and fourth time, and so on: we've programmed ourselves into an infinite loop We need to increment pos 1 past the element found prior to each subsequent iteration of the loop:
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// ok: corrected loop iteration while (( pos = namefind_first_of( numerics, pos )) != string::npos ) { cout "found numeric at index: " pos "\telement is " name[pos] endl; // move 1 past element found ++pos; }
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To find the embedded white space within our line of text, we simply replace numerics with a string containing the possible white
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space characters we might encounter However, if we are certain that only a blank space is used, we can explicitly supply a single character For example:
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// program fragment while (( pos = textlinefind_first_of( ' ', pos )) != string::npos ) //
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To mark the length of each word, we introduce a second positional object, as follows:
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// program fragment // pos: index 1 past word // prev_pos: index beginning of word string::size_type pos = 0, prev_pos = 0; while (( pos = textlinefind_first_of( ' ', pos )) != string::npos ) { // do something with string // now adjust positional markers prev_pos = ++pos; }
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For each iteration of our loop, prev_pos indexes the beginning of the word, and pos holds the index 1 past the end of the word (the position of the space) The length of each identified word, then, is marked by the expression
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pos - prev_pos; // marks length of word
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Now that we've identified the word, we need to copy it and then tuck it away in a string vector One strategy for copying the word is to loop through textline from prev_pos to 1 less than pos, copying each character in turn, in effect extracting the substring marked by the two indexes Rather than do that ourselves, however, the sub-str() string operation does it:
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// program fragment vector<string> words; while (( pos = textlinefind_first_of( ' ', pos )) != string::npos ) { wordspush_back( textlinesubstr( prev_pos, pos-prev_pos)); prev_pos = ++pos; }
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The substr() operation generates a copy of a substring of an existing string object Its first argument indicates the start position within the string The optional second argument indicates the length of the substring (if we omit the second argument, the remainder of the string is copied)
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