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method cannot be overridden An overriding method cannot exhibit behavior that contradicts the declaration of the original method An overriding method, therefore, cannot declare that it throws checked exceptions that cannot be thrown by the original method in the superclass 76 (g) It is not possible to invoke the doIt() method in A from an instance method in class C The method in C needs to call a method in a superclass two levels up in the inheritance hierarchy The supersuperdoIt() strategy will not work, since super is a keyword and cannot be used as an ordinary reference, nor accessed like a field If the member to be accessed had been a field, the solution would be to cast the this reference to the class of the field and use the resulting reference to access the field Field access is determined by the declared type of the reference, whereas the instance method to execute is determined by the actual type of the object denoted by the reference 77 (e) The code will compile without errors None of the calls to a max() method are ambiguous When the program is run, the main() method will call the max() method in C with the parameters 13 and 29 This method will call the max() method in B with the parameters 23 and 39 The max() method in B will in turn call the max() method in A with the parameters 39 and 23 The max() method in A will return 39 to the max() method in B The max() method in B will return 29 to the max() method in C The max() method in C will return 29 to the main() method 78 (c) The simplest way to print the message in the class Message would be to use msgtext The main() method creates an instance of MyClass, which results in the creation of a Message instance The field msg denotes this Message object in MySuperclass and is inherited by the MyClass object Thus, the message in the Message object can be accessed directly by msgtext in the print() method of MyClass 79 (b) and (g) (a) and (1) do not have covariant return types (b) overrides (2) The instance method in (c) cannot override the static method at (4) The static method in (d) and the static method at (4) do not have compatible return types The static method in (e) cannot override the instance method at (3) The instance method in (f) and the instance method at (5) do not have compatible return types The instance method in (g) overrides the instance method at (6), and they have covariant return types
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APPENDIX D
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(g) In the class Car, the static method getModelName() hides the static method of the same name in the superclass Vehicle In the class Car, the instance method getRegNo() overrides the instance method of the same name in the superclass Vehicle The declared type of the reference determines the method to execute when a static method is called, but the actual type of the object at runtime determines the method to execute when an overridden method is called
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(d) Note that the method equals() in the class Item overloads the method with the same name in the Object class Calls to overloaded methods are resolved at compile-time Using the reference itemA of the type Item results in the equals() method of the Item to be executed, and using the reference itemC of the type Object results in the equals() method of the Object class to be executed This is a canonical example where using the @Override annotation in front of the equals() method would be very useful
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(e) The class MySuper does not have a default constructor This means that constructors in subclasses must explicitly call the superclass constructor and provide the required parameters The supplied constructor accomplishes this by calling super(num) in its first statement Additional constructors can accomplish this either by calling the superclass constructor directly using the super() call, or by calling another constructor in the same class using the this() call which, in turn, calls the superclass constructor (a) and (b) are not valid, since they do not call the superclass constructor explicitly (d) fails, since the super() call must always be the first statement in the constructor body (f) fails, since the super() and this() calls cannot be combined
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(b) In a subclass without any declared constructors, the implicit default constructor will call super() The use of the super() and this() statements are not mandatory as long as the superclass has a default constructor If neither super() nor this() is declared as the first statement in the body of a constructor, then the default super() will implicitly be the first statement A constructor body cannot have both a super() and a this() statement Calling super() will not always work, since a superclass might not have a default constructor
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(d) The program will print 12 followed by Test When the main() method is executed, it will create a new instance of B by passing "Test" as argument This results in a call to the constructor of B that has one String parameter The constructor does not explicitly call any superclass constructor but, instead, the default constructor of the superclass A is called implicitly The default constructor of A calls the constructor in
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