The FloatMap can have more than two floats in each position, but only the first two are used in Java

Generation QR Code in Java The FloatMap can have more than two floats in each position, but only the first two are used
The FloatMap can have more than two floats in each position, but only the first two are used
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In this example, we are going to use an image as the input source, so we create a map that has the same dimensions as the image itselfThe code on lines 4 to 6 declares the FloatMap, setting its dimensions from the width and height of the imageThe nested loops on lines 9 to 14 initialize the FloatMap, assigning two samples for each element Each sample has the value -05, which is the offset that we require Note how these samples are installed:
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mapsetSample(i, j, 0, -050); mapsetSample(i, j, 1, -050); // The x offset // The y offset
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FloatMap has several overloaded variants of the setSample() function that you can use In the variant that we use here, the first two arguments are the x and y coordinates of the element, the third argument is the band number, and the fourth argument is the offset for that band Band 0 is used for the x-offset and band 1 for the y offset6 Now, here s the code that creates and uses the DisplacementMap effect: var scene: Scene; Stage { title: "DisplacementMap #1" scene: scene = Scene { width: 500 height: 380 fill: ColorBLACK content: [ ImageView { translateX: bind (scenewidth - imgWidth) / 2 translateY: bind (sceneheight - 30 - imgHeight) / 2 image: image effect: DisplacementMap { mapData: map } } ] } }
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As you can see, the effect is applied simply by creating a DisplacementMap based on the map data and installing it in an ImageView that contains the source imageWe don t need to set the scale or offset values because we are using the defaults in this caseYou can see the result in Figure 20-25
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The band numbers appear in the original equations map[x, y][0] indicates the value in band 0 at the element in position (x, y) in the map
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Figure 20-25
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A simple DisplacementMap effect
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The original image is shown on the left of the figure and the result of applying the on the rightAs you can see, the image has been moved halfway across and halfway down the area occupied by the source It s easy to see why this has happened if you look back at the equation that describes this effect:
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DisplacementMap dst[x, y] = src[x - 05 * srcWidth, y - 05 * srcHeight]
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This says that the pixel at (x, y) comes from the source pixel that is half the source width to its left and half the source height above it In other words, the image is moved down and to the rightTo make this more obvious still, let s add some concrete numbers We ll start by with the pixel at (0, 0) in the destination image According to the equation above, the color for this pixel comes from the pixel at (0 05 * 340, 0 05 * 255) = ( 170, 127) Because there is no such point, this pixel is not set, so this part of the destination is transparent In fact, every pixel for which either of the source coordinates is negative will be transparentThe first pixel in the destination image that will not be transparent is the one at (170, 127), which gets its color from the pixel at (0, 0) in the source By following this reasoning for any given pixel in the destination image, it is easy to see why the result of this effect is to move the source down and to the right, as shown in Figure 20-25 The wrap Variable You can achieve a slightly different effect to that shown above by setting the wrap variable of the DisplacementMap object to trueWhen you do this, the parts of the destination that would have been transparent because they correspond to points in the source image that are outside of its bounds (for example, those with negative coordinates) are populated by wrapping the coordinates modulo the size of the sourceThis means, for example, that the pixel at (0,0), which should come from ( 170, 127) in the source, will actually come from ( 170 + 340, 127 + 128), or (170, 1)You can see the overall effect of this by run-
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