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p r i n t f ("%c %c\nW, getchar(), g e t c h a r 0 1 :
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the first input character could be printed second instead of first In
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the value of errno may be evaluated before log is called There are rules for when certain expressions are evaluated By definition, all side effects and function calls must be completed at each semicolon, or when a function is called The && and I I operators execute left to right and only as far as necessary to determine their truth value (including side effects) The condition in a : operator is evaluated (including side effects) and then exactly one of the two expressions that follow is evaluated Java has a stricter definition of order of evaluation It requires that expressions, including side effects, be evaluated left to right, though one authoritative manual advises not writing code that depends "crucially" on this behavior This is sound advice if there's any chance that Java code will be converted to C or C++, which make no such promises Converting between languages is an extreme but occasionally reasonable test of portability
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Signedness of char In C and C u , it is not specified whether the char data type is signed or unsigned This can lead to trouble when combining chars and i nts, such as in code that calls the i nt-valued routine getchar() If you say
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char c ; /* should be i n t c = getchar0 ;
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PORTABILITY
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the value of c will be between 0 and 255 if char is unsigned, and between - 128 and 127 if char is signed, for the almost universal configuration of 8-bit characters on a two's complement machine This has implications if the character is to be used as an array subscript or if it is to be tested against EOF, which usually has value -1 in s t d i o For instance, we had developed this code in Section 61 after fixing a few boundary conditions in the original version The comparison s [ i ] == EOF will always fail if char is unsigned:
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int i ; charsCMAX]; f o r (i = 0 ; i < MAX-1; i++) i f ( ( s [ i ] = getchar()) == ' \ n ' break; s[i]='\O';
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== EOF)
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When getchar returns EOF, the value 255 (OxFF, the result of converting -1 to unsigned char) will be stored in s [ i ] If s [ i ] is unsigned, this will remain 255 for the comparison with EOF, which will fail Even if char is signed, however, the code isn't correct The comparison will succeed at EOF, but a valid input byte of OxFF will look just like EOF and terminate the loop prematurely So regardless of the sign of char, you must always store the return value of getchar in an i n t for comparison with EOF Here is how to write the loop portably:
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== EOF)
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s [ i ] = '\O1;
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Java has no unsigned qualifier; integral types are signed and the (16-bit) char type is not
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Arithmetic or logical shift Right shifts of signed quantities with the >> operator may be arithmetic (a copy of the sign bit is propagated during the shift) or logical (zeros fill the vacated bits during the shift) Again, learning from the problems with C and C++, Java reserves >> for arithmetic right shift and provides a separate operator >>> for logical right shift Byte order The byte order within short, i n t , and l o n g is not defined; the byte with the lowest address may be the most significant byte or the least significant byte This is a hardware-dependent issue that we'll discuss at length later in this chapter
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