def product(a, b, c): return a * b * c # here, * is the multiplication operator in Java

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def product(a, b, c): return a * b * c # here, * is the multiplication operator
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we can call it with three arguments, or by using starred arguments:
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>>> 30 >>> >>> 30 >>> 30 product(2, 3, 5) L = [2, 3, 5] product(*L) product(2, *L[1:])
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Syntax Lappend(x) Lcount(x) Lextend(m) L += m Lindex(x, start, end) Linsert(i, x) Lpop() Lpop(i) Lremove(x) Lreverse() Lsort()
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Appends item x to the end of list L Returns the number of times item x occurs in list L Appends all of iterable m s items to the end of list L; the operator += does the same thing Returns the index position of the leftmost occurrence of item x in list L (or in the start:end slice of L); otherwise, raises a ValueError exception Inserts item x into list L at index position int i Returns and removes the rightmost item of list L Returns and removes the item at index position int i in L Removes the leftmost occurrence of item x from list L, or raises a ValueError exception if x is not found Reverses list L in-place Sorts list L in-place; this method accepts the same key and reverse optional arguments as the built-in sorted()
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sorted()
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In the rst call we provide the three arguments normally In the second call we use a starred argument what happens here is that the three-item list is unpacked by the * operator, so as far as the function is concerned it has received the three arguments it is expecting We could have achieved the same thing using a 3-tuple And in the third call we pass the rst argument conventionally, and the other two arguments by unpacking a two-item slice of the L list Functions and argument passing are covered fully in 4 There is never any syntactic ambiguity regarding whether operator * is the multiplication or the sequence unpacking operator When it appears on the left-hand side of an assignment it is the unpacking operator, and when it appears elsewhere (eg, in a function call) it is the unpacking operator when used as a unary operator and the multiplication operator when used as a binary operator We have already seen that we can iterate over the items in a list using the syntax for item in L: If we want to change the items in a list the idiom to use is:
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for i in range(len(L)): L[i] = process(L[i])
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The built-in range() function returns an iterator that provides integers With one integer argument, n, the iterator range() returns, producing 0, 1, , n - 1
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3 Collection Data Types Deleting Items Using the del Statement
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Although the name of the del statement is reminiscent of the word delete, it does not necessarily delete any data When applied to an object reference that refers to a data item that is not a collection, the del statement unbinds the object reference from the data item and deletes the object reference For example:
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>>> x = 8143 # object ref 'x' created; int of value 8143 created >>> x 8143 >>> del x # object ref 'x' deleted; int ready for garbage collection >>> x Traceback (most recent call last): NameError: name 'x' is not defined
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When an object reference is deleted, Python schedules the data item to which it referred to be garbage-collected if no other object references refer to the data item When, or even if, garbage collection takes place may be nondeterministic (depending on the Python implementation), so if any cleanup is required we must handle it ourselves Python provides two solutions to the nondeterminism One is to use a try finally block to ensure that cleanup is done, and another is to use a with statement as we will see in 8 When del is used on a collection data type such as a tuple or a list, only the object reference to the collection is deleted The collection and its items (and for those items that are themselves collections, for their items, recursively) are scheduled for garbage collection if no other object references refer to the collection For mutable collections such as lists, del can be applied to individual items or slices in both cases using the slice operator, [] If the item or items referred to are removed from the collection, and if there are no other object references referring to them, they are scheduled for garbage collection We could use this technique to increment all the numbers in a list of integers For example:
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