3: Operators and Control Flow in Visual C#.NET

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3: Operators and Control Flow
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As shown in Figure 32, each box corresponds to a value of 2 raised to the power shown The value of the byte (8-bit number) is the sum of the powers of 2 of all of the eight bits that are set to 1
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7= 4 + 2 + 1
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Figure 32: Calculating the Value of an Unsigned Byte
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The binary translation just described is significantly different for signed numbers Signed numbers (long, short, int) are represented using a 2s complement notation This is so that addition continues to work when adding a negative number to a positive number as though both were positive operands With this notation, negative numbers behave differently than positive numbers Negative numbers are identified by a 1 in the leftmost location If the leftmost location contains a 1, you add the locations with 0s rather than the locations with 1s Each location corresponds to the negative power of 2 value Furthermore, from the result, it is also necessary to subtract 1 This is demonstrated in Figure 33
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0 = -4
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1 +0
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Figure 33: Calculating the Value of a Signed Byte
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Therefore, 1111 1111 1111 1111 corresponds to 1 and 1111 1111 1111 1001 holds the value 7 1000 0000 0000 0000 corresponds to the lowest negative value that a 16-bit integer can hold
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Shift Operators (<<, >>, <<=, >>=) Sometimes you want to shift the binary value of a number to the right or left In executing a left shift, all bits in a number s binary representation are shifted to the left by the number of locations specified by the operand on the right of the shift operator Zeroes are then used to backfill the locations on the right side of the binary number A right-shift operator does almost the
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Bitwise Operators ( <<, >>, |, &, ^, ~)
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same thing in the opposite direction However, if the number is negative, then the values used to backfill the left side of the binary number are ones and not zeroes The shift operators are >> and <<, the right-shift and leftshift operators, respectively In addition, there are combined shift and assignment operators, <<= and >>= Consider the following example Suppose you had the int value -7, which would have a binary representation of 1111 1111 1111 1111 1111 1111 1111 1001 In Listing 337, you right-shift the binary representation of the number 7 by two locations
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Listing 337: Using the Right-Shift Operator
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int x; x = (-7 >> 2); // 11111111111111111111111111111001 becomes // 11111111111111111111111111111110 // Write out "x is -2" SystemConsoleWriteLine("x = {0}", x);
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Output 317 shows the results of Listing 337
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OUTPUT 317:
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x = -2
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Because of the right shift, the value of the bit in the rightmost location has dropped off the edge and the negative bit indicator on the left shifts by two locations to be replaced with 1s The result is -2
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Bitwise Operators (&, |, ^) In some instances, you might need to perform logical operations, such as AND, OR, and XOR, on a bit-by-bit basis for two operands You do this via the &, |, and ^ operators, respectively
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BEGINNER TOPIC Logical Operators Explained If you have two numbers, as shown in Figure 34, the bitwise operations will compare the values of the locations beginning at the leftmost significant
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3: Operators and Control Flow
value and continuing right until the end The value of 1 in a location is treated as true, and the value of 0 in a location is treated as false
Figure 34: The Numbers 12 and 7 Represented in Binary
Therefore, the bitwise AND of the two values in Figure 34 would be the bit-by-bit comparison of bits in the first operand (12) with the bits in the second operand (7), resulting in the binary value 000000100, which is 4 Alternatively, a bitwise OR of the two values would produce 00001111, the binary equivalent of 15 The XOR result would be 00001011, or decimal 11 Listing 338 demonstrates how to use these bitwise operators The results of Listing 338 appear in Output 318