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where, as usual, condition1 and condition2 are conditions-expressions that yield truth values The || expression yields a bool, which is true if either of the conditions is true The || operator has lower precedence than the relational operators, and, like most C++ binary operators, is left-associative Moreover, it has a property that most other C++ operators do not share: If a program finds that the left operand of || is true, it does not evaluate the right operand at all This property is often called short-circuit evaluation, and as we shall see in 56/89, it can have a crucial effect on how we write our programs Because || is left-associative, and because of the relative precedence of ||,== ,and -,
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r == 0 || r == rows - 1 || c == 0 || c == cols - 1
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means the same as it would if we were to place all of its subexpressions in parentheses:
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((r == 0 || r == (rows - 1)) || c == 0) || c == (cols - 1)
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In order to evaluate this latter expression using the short-circuit strategy, the program first evaluates the left operand of the outermost ||, which is
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(r == 0 || r == (rows - 1)) || c == 0
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To do so, it must first evaluate the left operand of this inner ||, which is
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r == 0 || r == (rows - 1)
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This document is created with the unregistered version of CHM2PDF Pilot
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which, in turn, means evaluating
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r == 0
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If r is equal to 0, then each of the expressions
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must be true If r is nonzero, the next step is to compare r with rows - 1 If that test fails, then the program will compare c with zero, and if that fails, it will compare c with cols - 1 to determine the final result In other words, when we write a series of conditions separated by || operators, we are asking the program to test each of these conditions in turn If any of the inner conditions is true, then the whole condition is true; otherwise, the whole condition is false Each || operator stops as soon as it can determine its result, so if any of the inner conditions is true, the subsequent conditions go untested If we step back from the details, we should be able to see that these four equality tests are checking whether we are in the first row, the last row, the first column, or the last column, and, therefore, that the if statement writes an asterisk if we're in the top or bottom row, or if we're in the first or last column Otherwise, it does something else, which we must now define
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242 Writing nonborder characters
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It is now time to write the statements that correspond to the comments that say
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// write one or more nonborder characters // adjust the value of c to maintain the invariant
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in the program fragment in 241/23 These statements must deal with the characters that are not part of the border It should be easy to see that each of these characters is either a space or part of the greeting The only problem is figuring out which one it is, and what to do about it We begin by testing whether we are about to write the first character of the greeting, which we do by finding if we're in the correct row and on the correct column within that row The row we seek is the one after we've written the initial row of asterisks, followed by pad additional rows The appropriate column comes after we have written the initial asterisk on this row, followed by pad spaces Our knowledge of the invariants tells us that we're on the right row when r is equal to pad + 1, and be at the appropriate column when c is equal to pad + 1 In other words, to determine whether we are about to write the first character of the greeting, we must check whether r and c are both equal to pad + 1 If we've reached the right place to write the greeting, we'll do so; otherwise, we'll write a space instead In both cases, we have to remember to update c appropriately:
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if (r == pad + 1 && c == pad + 1) { std::cout << greeting; c += greetingsize(); } else { std::cout << " "; }
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The condition inside the if statement uses the logical-and operator As with the || operator, the && operator tests two conditions and yields a truth value It is left-associative and uses a short-circuit evaluation strategy Unlike the || operator, the && operator yields true only if both conditions are true If either condition is false, the result of && is false The second condition will be tested if and only if the first condition is true