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Since there is no concept of undo or redo, the UndoRedo property is always
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We begin by getting the Participants group To get there, we could have just used MainDataSource to get the root and then SelectSingleNode with the XPath /my:myFields/my:Participants Instead, we wanted to show how the XPathNavigator can be used as a cursor to traverse the data source The sender object in all XML events will always be the XPathNavigator behind the speci c event handler So in this case we know that sender will be LastName (Recall that eSite is the XPathNavigator that initiated the event; if the event handler is sinking group XML events, eSite can be any child node) After we move to the Participants group, we pass the navigator to the SortChildNodes method, which does the actual bubble sort Listing 1517 shows the implementation of the sort The SortChildNodes method rst needs to know the total number of participant items to sort To get the number of Participant groups, we count the result of selecting all Participant children of the Participants group The two for loops account for the bubble sort iterations To compare the last names of participant j and participant j+1, we select the nodes by using XPath with a predicate lter A predicate lter is signi ed by square brackets within an XPath expression Passing a simple numerical value like [1] is a shortcut for [position()=1] (You can nd more on the XPath Language at the W3C site, as referenced in the Appendix) StringCompare performs a culture-speci c string comparison that returns 1 if child1 s value is lexicographically later than that of child2 If
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Listing 1517: Sorting Participants (by LastName) in the Data Source
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public void SortChildNodes(XPathNavigator parent) { const string Prtpnt = "Participant"; XPathNodeIterator childNodes = parentSelectChildren(Prtpnt, parentNamespaceURI); int numberChildren = childNodesCount; for (int i = 1; i <= numberChildren; i++) for (int j = 1; j <= numberChildren - i; j++) { XPathNavigator child1, child2; child1 = parentSelectSingleNode( "my:" + Prtpnt + "[" + j + "]/my:LastName", NamespaceManager); child2 = parentSelectSingleNode( "my:" + Prtpnt + "[" + (j+1) + "]/my:LastName", NamespaceManager); if (stringCompare(child1Value, child2Value) > 0) { child1MoveToParent(); child2MoveToParent(); XPathNavigator temp = child1Clone(); child1ReplaceSelf(child2); child2ReplaceSelf(temp); } } }
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that s the case, we want to swap the positions of the child1 and child2 parent nodes (The parent nodes of child1 and child2 represent entire rows in the Repeating Table) Since XPathNavigator objects are simply pointers to the underlying data source, we cannot assign new objects to them Instead, navigators expose methods such as Clone, to make a deep copy, and ReplaceSelf, to swap out (and remove) the node for another We use a combination of these methods to swap the positions of child1 and child2 Participant groups
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Are you wondering why the bubble sort loops start with 1 instead of 0 Repeating items are addressed in XPath by using a 1-based index
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Since the SortChildNodes method is called only from the LastName_ Changed event handler, it runs only when a LastName eld is modi ed What if the form template is opened with an already existing form whose underlying participants data is unsorted Currently, it won t be sorted However, by sinking the Loading form event, you could call SortChildNodes to ensure the data is sorted from the start If a form is opened with a huge amount of data that s sorted in descending (Z to A) order (the worst case for the bubble sort algorithm), loading performance could be lethargic Consider showing the user a Please wait message if this is a concern However, we recommend using a more ef cient algorithm such as merge or binary tree sorting, which take less time to run in their worst cases
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When posting data back to the server takes a long time (which includes running custom form code), Forms Services automatically shows the Sending data to the server busy dialog over the form in the browser
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