Distinguishing Overloading from Redeclaring a Function in .NET framework

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Distinguishing Overloading from Redeclaring a Function
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Table of Contents | Index
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If the return type and parameter list of two functions declarations match exactly, then the second declaration is treated as a redeclaration of the first If the parameter lists of two functions match exactly but the return types differ, then the second declaration is an error:
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This popular tutorial introduction to standard C++ has been completely updated, reorganized, and rewritten to help programmers learn the language faster and use it in a more modern, effective wayJust as C++ has evolved since the last edition,Record lookup(const toAccount&); now introduce the C++ standard library from the beginning, giving so has the authors' approach teaching it They readers the means to write useful programs without first having toonly return type is different Highlighting today's best bool lookup(const Account&); // error: master every language detail practices, they show how to write programs that are safe, can be built quickly, and yet offer outstanding performance Examples that take advantage of the library, and explain the features of C++, also show how to make the best use of the language As in its previous editions, the book's authoritative discussion of fundamental C++ concepts and techniques makes it a valuable resource even for more experienced programmersProgram Faster and More Effectively with This Rewritten Functions cannot be overloaded based only on differences in the return type Classic Restructured for quicker learning, using the C++ standard library Updated to teach the most current programming styles and program lists techniques Filled with even if they don't look the same: Two parameter design can be identical, new learning aids that emphasize important points, warn about common pitfalls, suggest good programming practices, and provide general usage tips Complete with exercises that reinforce skills learned Authoritative and comprehensive in its coverageThe source code for the book's extended examples is available on the Web at the address below the same function // each pair declares
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Record lookup(const Account &acct); Record lookup(const Account&); // parameter names are ignored typedef Phone Telno; Record lookup(const Phone&); Record lookup(const Telno&); // Telno and Phone are the same type Record lookup(const Phone&, const Name&); // default argument doesn't change the number of parameters Record lookup(const Phone&, const Name& = ""); // const is irrelevent for nonreference parameters Record lookup(Phone); Record lookup(const Phone); // redeclaration
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In the first pair, the first declaration names its parameter Parameter names are only a documentation aid They do not change the parameter list In the second pair, it looks like the types are different, but Telno is not a new type; it is a synonym for Phone A typedef name provides an alternative name for an existing data type; it does not create a new data type Therefore, two parameters that differ only in that one uses a typedef and the other uses the type to which the typedef corresponds are not different In the third pair, the parameter lists differ only in their default arguments A default argument doesn't change the number of parameters The function takes two arguments, whether they are supplied by the user or by the compiler The last pair differs only as to whether the parameter is const This difference has no effect on the objects that can be passed to the function; the second declaration is treated as a redeclaration of the first The reason follows from how arguments are passed When the parameter is copied, whether the parameter is const is irrelevantthe function executes on a copy Nothing the function does can change the argument As a result, we can pass a const object to either a const or nonconst parameter The two parameters are indistinguishable
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It is worth noting that the equivalence between a parameter and a const parameter applies only to nonreference parameters A function that takes a const reference is different from on that takes a nonC++ Primer, Fourth Edition const reference Similarly, a function that takes a pointer to a const type differs from a function that takes Jos e Lajoie, to the nonconst object of the same type By Stanley B Lippman, a pointer
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Barbara E Moo Publisher:Addison Wesley Professional Pub Date: February 14, 2005 Print ISBN: 0-201-72148-1 Pages: 912
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