Deciphering File Formats in .NET

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Deciphering File Formats
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00401E9B 00401E9D 00401EA0 00401EA5 00401EA9 00401EAD 00401EAF 00401EB1 00401EB3 00401EB7 00401EB8 00401EBD 00401EBF 00401EC2 00401EC6 00401EC7 00401ECD 00401ED1 00401ED7 00401ED8 00401EDA 00401EDB 00401EDD 00401EE1 00401EE2 00401EE3 00401EE4 00401EE5 00401EEA 00401EED
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CALL EBP ADD ESP,4 MOV ECX,4 LEA EDI,SS:[ESP+6C] LEA ESI,SS:[ESP+5C] XOR EDX,EDX REPE CMPS DWORD PTR ES:[EDI],DWORD PTR DS:[ESI] JE SHORT cryptex.00401EC2 MOV EAX,SS:[ESP+18] PUSH EAX PUSH cryptex.004033B4 ; ASCII ERROR: File %s is corrupted! CALL EBP ADD ESP,8 MOV ECX,SS:[ESP+1C] PUSH ECX CALL DS:[<&ADVAPI32.CryptDestroyHash>] MOV EDX,SS:[ESP+14] MOV ESI,DS:[<&KERNEL32.CloseHandle>] PUSH EDX ; /hObject CALL ESI ; \CloseHandle PUSH EBX ; /hObject CALL ESI ; \CloseHandle MOV ECX,SS:[ESP+7C] POP ESI POP EBP POP EDI POP EBX CALL cryptex.004027C9 ADD ESP,70 RETN
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Listing 6.8 (continued)
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Let s begin with a quick summary of the most important operations performed by the function in Listing 6.8. The function starts by opening the archive file. This is done by calling a function at 00401670, which opens the archive and proceeds to call into the header and password verification function at 004011C0, which you analyzed in Listing 6.3. After 00401670 returns the function proceeds to create a hash object of the same type you saw earlier that was used for calculating the password hash. This time the algorithm type is 0x8003, which is ALG_SID_MD5. The purpose of this hash object is still unclear. The code then proceeds to read the Cryptex header into the same global variable at 00406058 that you encountered earlier, and to search the file list for the relevant file entry.
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Scanning the File List
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The scanning of the file list is performed by calling a function at 004017B0, which goes through a familiar route of scanning the file list and comparing each name with the name of the file being extracted. Once the correct item is found the function retrieves several fields from the file entry. The following is the code that is executed in the file searching routine once a file entry is found.
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00401881 00401885 00401888 0040188A 0040188C 0040188E 00401892 00401895 00401899 0040189B 0040189F 004018A1 004018A3 004018A6 004018A8 004018AA 004018AD 004018B0 004018B3 004018B6 004018B9 004018BC MOV ECX,SS:[ESP+10] LEA EAX,DS:[ESI+ESI*4] ADD EAX,EAX ADD EAX,EAX SUB EAX,ESI MOV EDX,DS:[ECX+EAX*8+8] LEA EAX,DS:[ECX+EAX*8] MOV ECX,SS:[ESP+24] MOV DS:[ECX],EDX MOV ECX,SS:[ESP+28] TEST ECX,ECX JE SHORT cryptex.004018BC LEA EDX,DS:[EAX+C] MOV ESI,DS:[EDX] MOV DS:[ECX],ESI MOV ESI,DS:[EDX+4] MOV DS:[ECX+4],ESI MOV ESI,DS:[EDX+8] MOV DS:[ECX+8],ESI MOV EDX,DS:[EDX+C] MOV DS:[ECX+C],EDX MOV EAX,DS:[EAX+4]
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First of all, let s inspect what is obviously an optimized arithmetic sequence of some sort in the beginning of this sequence. It can be slightly confusing because of the use of the LEA instruction, but LEA doesn t have to deal with addresses. The LEA at 00401885 is essentially multiplying ESI by 5 and storing the result in EAX. If you go back to the beginning of this function, it is easy to see that ESI is essentially employed as a counter; it is initialized to zero and then incremented by one with each item that is traversed. However, once all file entries in the current cluster are scanned (remember there are 0x1A entries), ESI is set to zero again. This implies that ESI is used as the index into the current file entry in the current cluster. Let s return to the arithmetic sequence and try to figure out what it is doing. You ve already established that the first LEA is multiplying ESI by 5. This is followed by two ADDs that effectively multiply ESI by itself. The bottom line is that ESI is being multiplied by 20 and is then subtracted by its original value. This is equivalent to multiplying ESI by 19. Lovely isn t it The next line at 0040188E actually uses the outcome of this computation (which is now in EAX) as an
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