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iter_swap() swaps the values contained within the elements addressed by the two ForwardIterators a and b
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#include <algorithm> #include <list> #include <iostreamh> int main() { int ia[] = { 5, 4, 3, 2, 1, 0 }; list< int,allocator > ilist( ia, ia+6 ); typedef list< int, allocator >::iterator iterator; iterator iter1 = ilistbegin(), iter2, iter_end = ilistend(); // bubble sort the list for ( ; iter1 != iter_end; ++iter1 ) for ( iter2 = iter1; iter2 != iter_end; ++iter2 ) if ( *iter2 < *iter1 ) iter_swap( iter1, iter2 ); // output generated: // ilist after bubble sort using iter_swap(): // { 0 1 2 3 4 5 } cout "ilist afer bubble sort using iter_swap(): { "; for ( iter1 = ilistbegin(); iter1 != iter_end; ++iter1 ) cout *iter1 " "; cout "}\n"; } lexicographical_compare() template <class InputIterator1, class InputIterator2 > bool lexicographical_compare( InputIterator1 first1, InputIterator1 last1, InputIterator2 first2, InputIterator2 last2 ); template < class InputIterator1, class InputIterator2, class Compare > bool lexicographical_compare( InputIterator1 first1, InputIterator1 last1, InputIterator2 first2, InputIterator2 last2, Compare comp );
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lexicographical_compare() compares the corresponding pair of elements of the two sequences identified by [first1,last1) and [first2,last2) The comparison continues until either the element pair does not match, the pair [last1,last2] is reached, or either last1 or last2 is reached (if the sequences are not of equal size) For the first pair of elements that do not match, the following occurs:
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If the element of the first sequence is less, return true; otherwise, return false If last1 is reached, but last2 is not, return true If last2 is reached, but last1 is not, return false
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If both last1 and last2 are reached (all the elements match), return false; that is, the first sequence is not lexicographically less than the second sequence
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For example, given the following two sequences
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string arr1[] = { "Piglet", "Pooh", "Tigger" }; string arr2[] = { "Piglet", "Pooch", "Eeyore" };
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the algorithm matches on the first element pair, but does not match on the second Pooh evaluates as greater than Pooch because the c is lexicographically less than h (think of the comparison as the ordering done of words listed within a dictionary) The algorithm stops at this point (the third elements are never compared) The result of the comparison is false The second version of the algorithm takes a predicate comparison object rather than using the less than operator of the underlying element type
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#include <algorithm> #include <list> #include <string> #include <asserth> #include <iostreamh> class size_compare { public: bool operator()( const string &a, const string &b ) { return alength() <= blength(); } }; int main() { string arr1[] = { "Piglet", "Pooh", "Tigger" }; string arr2[] = { "Piglet", "Pooch", "Eeyore" }; bool res; // evaluates to false at second element // Pooch is less than Pooh // would also evaluate false at third element res = lexicographical_compare( arr1, arr1+3, arr2, arr2+3 ); assert( res == false ); // evaluates to true: each element of ilist2 // has a length less than or equal to the // associated ilist1 element list< string, allocator > ilist1( arr1, arr1+3 ); list< string, allocator > ilist2( arr2, arr2+3 ); res = lexicographical_compare( ilist1begin(), ilist1end(), ilist2begin(), ilist2end(), size_compare() ); assert( res == true ); cout "ok: lexicographical_compare succeeded!\n"; } lower_bound() template< class ForwardIterator, class Type > ForwardIterator
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lower_bound( ForwardIterator first, ForwardIterator last, const Type &value ); template< class ForwardIterator, class Type, class Compare > ForwardIterator lower_bound( ForwardIterator first, ForwardIterator last, const Type &value, Compare comp );
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lower_bound() returns an iterator addressing the first position within the sorted sequence marked off by [first,last) into which value may be inserted without violating the sorted ordering of the container This position will mark off a value either greater than or equal to value For example, given the following sequence,
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int ia[] = {12,15,17,19,20,22,23,26,29,35,40,51};
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A call of lower_bound() with a value of 21 returns an iterator addressing the value 22 A call of lower_bound() with a value of 22 also returns an iterator addressing the value 22 The first version uses the less than operator of the underlying type; the second version orders the elements based on comp
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#include <algorithm> #include <vector> #include <iostreamh> int main() { int ia[] = {29,23,20,22,17,15,26,51,19,12,35,40}; sort( &ia[0], &ia[12] ); int search_value = 18; int *ptr = lower_bound( ia, ia+12, search_value ); // generates: // The first element 18 can be inserted in front of is 19 // The previous value is 17 cout "The first element " search_value " can be inserted in front of is " *ptr endl "The previous value is " *(ptr-1) endl; vector< int, allocator > ivec( ia, ia+12 ); // sort in descending order sort( ivecbegin(), ivecend(), greater<int>() ); search_value = 26; vector< int, allocator >::iterator iter; // have to tell it appropriate ordering // relationship to use in this case iter = lower_bound( ivecbegin(), ivecend(), search_value, greater<int>() ); // generates: // The first element 26 can be inserted in front of is 26 // The previous value is 29 cout "The first element "
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