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int main() { try { // main() function as defined in 162 } catch ( const out_of_range &excp ) { // prints: // out_of_range error in Array<elemType>::operator[]() cerr excpwhat() "\n"; return -1; } }
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With this implementation, an out-of-bounds index in the function try_array() causes the Array operator[]() to throw an exception of type out_of_range caught in main()
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Which exceptions might the following functions throw
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#include <stdexcept> (a) void operate() throw( logic_error ); (b) int mathOper( int ) throw( underflow_error, overflow_error ); (c) char manip( string ) throw( );
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Exercise 196
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Explain how C++ exception handling supports the programming technique known as "resource acquisition is initialization; resource release is destruction"
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Why is the list of catch clauses following the try block incorrect How would you fix it
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#include <stdexcept> int main() { try { // use of the C++ standard library } catch( exception ) { } catch( const runtime_error &re ) { } catch( overflow_error eobj ) { } }
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Given a basic C++ program,
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int main() { // use of the C++ standard library }
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modify main() to catch any exception thrown by functions in the C++ standard library The handlers should print the error message associated with the exception before calling abort () (defined in the header <cstdlib>) to terminate main()
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Overload Resolution and Inheritance
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All aspects of function overload resolution are influenced by class inheritance Recall that the three steps of function overload resolution are the following: 1 Select the candidate functions 2 Select the viable functions 3 Select the best match function (See Section 92 for a full discussion) The selection of the candidate functions is influenced by inheritance because the functions associated with the base classes, either their member functions or the functions declared in the namespaces where the base classes are defined, are considered when selecting the candidate functions The selection of viable functions is influenced by inheritance because a greater set of user-defined conversions are considered for the conversions of the arguments to the types of a viable function parameter The selection of best viable function is influenced by inheritance b cause it impacts the rank of the conversion sequences that can apply to an argument to convert it to the type of a function parameter In this section we examine the influence of inheritance on the three steps of function overload resolution in more detail Candidate Functions Inheritance impacts the first step of function overload resolution that of establishing the set of candidate functions for a call The influence of inheritance on this first step varies depending on whether the call is an ordinary function call of the form
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func( args );
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or whether the call is to a member function using the member access operators dot and arrow:
objectmemfunc( args ); pointer->memfunc( args );
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file:///F|/WinDDK/resources/CPPPrimer/c++primerhtm
In this subsection we look at how inheritance influences each situation in turn When an argument in an ordinary function call is of class type, a reference to class type, or a pointer to class type, and the class type is defined within a namespace, the functions declared in that namespace with the same name as the function called are candidate functions, even though these functions are not visible at the point of the call (this was presented in more detail in Section 1510) With inheritance, if the argument is of class type, a reference to class type, or a pointer to class type, and the class has base classes, the functions declared within the namespaces where the base classes are defined, and with the same name as the function called, are also added to the set of candidate functions For example:
namespace NS { class ZooAnimal { /* */ }; void display( const ZooAnimal& ); } // Bear's base class is declared in namespace NS class Bear : public NS::ZooAnimal { }; int main() { Bear baloo; display( baloo ); return 0; }
The argument baloo has class type Bear The candidate functions for the call to display() are not only the functions with declarations that are visible where the function display() is called, but also the functions in the namespace where the class Bear and its base class ZooAnimal are declared The function display(const ZooAnimal&) declared in namespace NS is added to the set of candidate functions If an argument is of class type and the class definition declares friend functions with the same name as the function that is called, these friend functions are candidate functions, even if the declarations for these friend functions are not visible at the point of the call (as presented in Section 1510) With inheritance, if the argument type is a class with base classes, the friend functions with the same name as the function that is called and declared within the base class definitions are also added to the set of candidate functions For example, let's instead declare the function display() shown previously as a friend function within the class ZooAnimal:
namespace NS { class ZooAnimal { friend void display( const ZooAnimal& ); }; } // Bear's base class is declared in namespace NS class Bear : public NS::ZooAnimal { }; int main() { Bear baloo; display( baloo ); return 0; }
The function argument baloo has type Bear Its base class ZooAnimal declares display() as a friend function display() is a
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