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One problem with this move toward polymorphism is that the general use of the subscript operator has gone from an inline memory access to a considerably more expensive virtual function call For example, in the following function, whichever type to which ia actually refers, a simple inline read of the element is all that is necessary:
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int find( const Array< int { for ( int ix = 0; ix < // now a virtual if ( ia[ ix ] == return ix; return -1; }
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> &ia, int value ) iasize(); ++ix ) function call value )
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To accommodate performance concerns, we provide an inline at() member function providing a direct read of the element
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A Range-Checking Array Class Derivation
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In the try_array() function of section 1613 used to exercise our earlier implementation of the Array class template, there is the following two-statement sequence:
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int index = iAfind( find_val ); Type value = iA[ index ];
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find() returns the index of the first occurrence of find_val, or -1 if the value does not occur within the array This code is incorrect because it does not test for a possible return value of - 1 Since -1 falls outside the array boundary, each initialization of value is potentially invalid; each execution of our program is potentially in error Let's define a range-checking Array subtype We'll call it Array_RC and define it in a header file named Array_RCh:
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#ifndef ARRAY_RC_H #define ARRAY_RC_H #include "Arrayh" template <class Type> class Array_RC : public virtual Array<Type> { public: Array_RC( int sz = ArraySize ) : Array<Type>( sz ) {} Array_RC( const Array_RC&r ); Array_RC( const Type *ar, int sz ); Type&operator[]( int ix ); }; #endif
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Within the definition of the derived class, each reference to the template base class type specifier must be fully qualified with its formal parameter list One writes
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Array_RC( int sz = ArraySize ) : Array<Type>( sz ) {}
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// error: Array is not a type specifier Array_RC( int sz = ArraySize ) : Array( sz ) {}
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The only specialized behavior of the Array_RC class is the range-checking performed by its subscript operator Otherwise, the Array class template implementation can be reused as is However, because constructors are not inherited, recall, the Array_RC class defines a set of three constructors The virtual derivation of Array_RC with Array anticipates the subsequent multiple derivation that we will look at later Here is the full Array_RC member function implementation placed in a file named Array_RCC (the Array function definitions are placed in an ArrayC header file because we use the inclusion model of template instantiation [see Section 1681 for a discussion]):
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#include "Array_RCh" #include "ArrayC" #include <asserth> template <class Type> Array_RC<Type>::Array_RC( const Array_RC<Type> &r ) : Array<Type>( r ) {} template <class Type> Array_RC<Type>::Array_RC( const Type *ar, int sz ) : Array<Type>( ar, sz ) {} template <class Type> Type &Array_RC<Type>::operator[]( int ix ) { assert( ix >= 0 &&ix < Array<Type>::_size ); return ia[ ix ]; }
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Why do we qualify the referenced members of the Array base class, such as the following qualification of _size
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Array<Type>::_size;
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We must do so to prevent the Array base class from being examined until the template is instantiated We do this by making the reference depend on the template parameter That is, the names in the definition of Array_RC are resolved when the template is defined, except for the names that depend explicitly on a template parameter When the unqualified name _size is used, the compiler must find a definition for _size unless the name depends explicitly on a template parameter The name _size is made to depend on the template parameter by prefixing it with the base class name Array<Type> The compiler then does not attempt to resolve name _size until the template is instantiated (We'll see more examples of this in the class definition of Array_Sort) Each instantiation of Array_RC generates an associated Array class instance For example,
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