Base MI Class Derived2 (i) pb = new (ii) pc = new in Java

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Base MI Class Derived2 (i) pb = new (ii) pc = new
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*pb; *pmi; *pc; *pd2; Class; Final;
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(iv)
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(iii) pmi = pb; pd2 = pmi;
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Exercise 1814
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Given the following class hierarchy, with the following members,
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class Base { public: bar( int ); // protected: int ival; // }; class Derived1 : virtual public Base { public: bar( char ); foo( char ); // protected: char cval; // }; class Derived2 : virtual public Base { public: foo( int ); // protected: int ival; char cval; // };
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class VMI : public Derived1, public Derived2 {};
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which inherited members can be accessed without qualification from within the VMI class Which require qualification
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Exercise 1815
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Given the following Base class with the following three constructors,
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class Base { public: Base(); Base( string ); Base( const Base&); // protected: string _name; };
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define the associated three constructors for the following:
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(b) (c)
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one of either class Derived1 : virtual public Base{ }; class Derived2 : virtual public Base{ }; class VMI : public Derived1, public Derived2{ }; class Final : public VMI{ };
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A Multiple, Virtual Inheritance Example In this section we illustrate the definition and use of a multiple, virtual hierarchy by implementing the Array class template hierarchy introduced in Section 24 We base our implementation on the Array class template presented in 16, but modified to serve as a concrete base class We preface our implementation with a brief introductory discussion of using class templates with inheritance An instance of a class template can serve as an explicit base class, such as the following:
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class IntStack : private Array<int> {};
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Alternatively, a class template can be derived from a nontemplate base class, such as the following,
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class Base {}; template < class Type > class Derived : public Base {};
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or serve as both a derived and base class of a derivation:
template < class Type > class Array_RC : public virtual Array<Type> {};
In the first example, the integer instantiation of the Array class template serves as a private base class of the nontemplate IntStack class In the second example, the nontemplate Base class serves as the base class of each Derived class template instantiation In the third example, each instantiation of the Array_RC class template has the associated Array class template instantiation as its base class For example,
Array_RC<int> ia;
generates an integer instance of both the Array and Array_RC class templates In addition, the template parameter itself can serve as a base class For example, [MURRAY93] illustrates this case,
template < typename Type > class Persistent : public Type{ };
which defines a derived persistent subtype for each instantiated type As Murray notes, an implicit constraint on Type is that it be a class type For example:
Persistent< int > pi; // oops, error
results in a compile-time error because the built-in types may not be the object of derivation When serving as a base class, a class template must be qualified with its full parameter list Given the following class template definition, for example,
template < class T > class Base {};
one writes
template < class Type > class Derived : public Base<Type> {};
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// error: Base is a template // and template arguments must be specified template < class Type > class Derived : public Base{};
In the next section, the Array class template defined in 16 serves as a virtual base class to (1) a range-checking Array subtype, (2) a sorted Array subtype, and (3) an Array sub-type that is both sorted and supports range-checking The original Array class template definition, however, is not suitable for derivation:
All its data members and auxiliary functions are private, not protected None of the type-dependent functions, such as the subscript operator, are specified as virtual
Does this mean that our original implementation was wrong No It was correct insofar as we understood it At the time of the original class template Array implementation, we hadn't realized the need for specialized Array subtypes Now that we do, however, we need to revise the Array class template definition (the member function implementation remains the same) Here is our new Array class template definition:
#ifndef ARRAY_H #define ARRAY_H #include <iostream> // needed for the forward declaration of operator template <class Type> class Array; template <class Type> ostream& operator ( ostream&, const Array<Type>&); template <class Type> class Array { static const int ArraySize = 12; public: explicit Array( int sz = ArraySize ) { init( 0, sz ); } Array( const Type *ar, int sz ) { init( ar, sz); } Array( const Array &iA ) { init( iAia, iAsize()); } virtual ~Array() { delete [] ia; } Array&operator=( const Array&); int size() { return _size; } virtual void grow(); virtual void print( ostream&= cout ); Type at( int ix ) const { return ia[ ix ]; } virtual Type&operator[]( int ix ) { return ia[ix]; } virtual void sort( int,int ); virtual int find( Type ); virtual Type min(); virtual Type max(); protected: void swap( int,int ); void init( const Type*, int ); int _size; Type *ia; }; #endif
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