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the four functions f() declared in global scope are visible at the point of the call They are therefore part of the set of candidate functions 2 If the type of a function argument is declared within a namespace, the namespace member functions that have the same name as the function called are added to the set of candidate functions For example:
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namespace NS { class C { /* */ }; void takeC( C& ); } // the type of cobj is class C declared in namespace NS NS::C cobj; int main() { // no takeC() visible at the point of the call takeC( cobj ); // ok: calls NS::takeC( C& ) // because the argument is of type NS::C // the function takeC() declared in // namespace NS is considered return 0; }
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The candidate functions are therefore the union of the functions visible at the point of the call and the functions declared within the namespaces of the argument types When we are identifying the set of overloaded functions visible at the point of the call, the rules we have seen earlier on how to build a set of overloaded functions still apply A function declared in a nested scope hides rather than overloads a function having the same name in an enclosing scope The candidate functions in such a situation are the functions declared in the nested scope, that is, the functions that are not hidden from the function call In the following example, the candidate functions visible at the point of the call are format(double) and format(char*):
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char* format( int ); void g() { char* format( double ); char* format( char* ); format(3); // calls format( double ) }
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Because the function format(int) declared in global scope is hidden, it is not included in the set of candidate functions The candidate functions can be introduced by using declarations that are visible at the point of the call Consider the following example:
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namespace libs_R_us { int max( int, int ); double max( double, double ); } char max( char, char ); void func() { // namespace functions not visible // the three calls call global function max( char, char ) max( 87, 65 ); max( 355, 766); max( 'J', 'L' ); }
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The functions max() defined in namespace libs_R_us are not visible at the point of the call The only function visible is the function max() declared in global scope This function is the only function in the set of candidate functions; it is the function called by all three calls located in func() We can use a using declaration to make the functions max() declared in namespace libs_R_us visible Where would we put the using declaration If we place the using declaration in global scope,
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char max( char, char ); using libs_R_us::max; // using declaration
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the functions max() from namespace libs_R_us are added to the set of overloaded functions containing the function max() declared in global scope All three functions are now visible within func() and become part of the set of candidate functions With all three functions visible at the point of the call, the calls in func() are resolved as follows:
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void func() { max( 87, 65 ); // calls libs_R_us::max( int, int ) max( 355, 766 ); // calls libs_R_us::max( double, double ) max( 'J', 'L' ); // calls ::max( char, char ) }
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But what if we had introduced the using declaration in the local scope of function func(), as follows
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void func() { // using declaration using libs_R_us::max; // function calls as above }
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Which functions max() would be included in the set of candidate functions Recall that using declarations nest With the using declaration in local scope, the global function max(char, char) is hidden The only visible functions at the point of the call are
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