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A set of overloaded functions can also be declared within a class Because each class maintains its own scope, the functions that are members of two distinct classes do not overload one another Class member functions are described in 13 Overload resolution for class member functions is described in 15 A set of overloaded functions can also be declared within a namespace Each namespace also maintains its own scope, and the functions that are members of two distinct namespaces do not overload one another For example:
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#include <string> namespace IBM { extern void print( const string < ); extern void print( double ); // overloads print() } namespace Disney { // separate scope: // does not overload IBM's print() functions extern void print( int ); }
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Using declarations and using directives are mechanisms by which namespace members can be made visible in other scopes These mechanisms have some impact on the declarations of overloaded functions Using declarations and using directives are introduced in Section 86 How does a using declaration work for an overloaded function Recall that a using declaration introduces an alias for a namespace member in the scope where the using declaration appears What happens with the using declarations in the following program
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namespace libs_R_us { int max( int, int ); int max( double, double ); extern void print( int ); extern void print( double ); } // using declarations: using libs_R_us::max; using libs_R_us::print( double ); // error void func() { max( 87, 65 ); // calls libs_R_us::max( int, int ) max( 355, 766 ); // calls libs_R_us::max( double, double ) }
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The first using declaration introduces both functions libs_R_us::max() in global scope It is then possible to call either max() function within func() The types of the arguments on the function call determine which function is called The second using declaration is an error A user cannot specify a parameter list in a using declaration for a function The only valid using declaration for libs_R_us::print() is
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using libs_R_us::print;
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A using declaration always declares aliases for all the functions in a set of overloaded functions Why is this restriction necessary This restriction ensures that the interface of the namespace libs_R_us is not violated It is clear that, for a function call such as
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the author of the namespace expects the function libs_R_us::print(inty) to be called The author of the library provided different functions for a reason Allowing users to selectively add to a scope one function in a set of overloaded functions but not all of the functions could lead to surprising program behavior What happens if a using declaration introduces a function in a scope in which a function of the same name already exists Recall that a using declaration is a declaration It is as if the functions introduced by the using declaration were declared where the using declaration appears For this reason, the functions introduced by the using declaration overload the other declarations of the functions with the same name already present in the scope where the using declaration appears For example:
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#include <string> namespace libs_R_us { extern void print( int ); extern void print( double ); } extern void print( const string & ); // libs_R_us::print( int ) and libs_R_us::print( double ) // overload print( const string & ) using libs_R_us::print; void fooBar( int ival ) { print( "Value: " ); // calls global print( const string & ) print( ival ); // calls libs_R_us::print( int ) }
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The using declaration adds two declarations to global scope: one for print(int) and one for print(double) These declarations alias the functions in namespace libs_R_us The declarations are added to the overload set for print(), of which the global function print(const string &) is already a member When a function call is found in fooBar(), all the print() functions are considered If the using declaration introduces a function in a scope that already has a function of the same name with the same parameter list, then the using declaration is in error A using declaration cannot declare the function print(int) to be an alias for the function in namespace libs_R_us if there already exists a function named print(int) in global scope For example:
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namespace libs_R_us { void print( int ); void print( double ); } void print( int ); using libs_R_us::print; // error: redeclaration of print(int) void fooBar( int ival ) { print( ival ); // which print ::print or libs_R_us::print }
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