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Introduction The answer to this question depends upon the type of file Some formats require that the most significant byte be stored first; others require that the least significant be first Why not order bytes in an image file so that a simple read operation like this reads integers correctly unsigned int value ; inputstreamread ((char *) &value, sizeof (value)) ; The problem is that different types of processors order integers differently, and blindly reading raw bytes into an integer variable will not work for all of them Most processors in common use, including the Motorola 680x0 and Sun SPARC families, store integers with the most significant byte first This byte ordering is known as big-endian It is also known as network order because it is used by Internet protocol Processors that store integers with the least significant byte first are known as little-endian The Intel 80x86 family of processors used in personal computers is the most common little-endian processor This code example produces different output depending upon whether it is run on a big-endian or a little-endian system #include <iostream> using namespace std ; main () { unsigned short value = 1 ; unsigned char *ptr = (unsigned char *) &value ; if (*ptr == 1) cout << "I'm Little-Endian" << endl ; else cout << "I'm Big-Endian" << endl ; return 0 ; } Converting between little-endian and big-endian formats is simply a matter of swapping bytes, and the conversion is the same in either direction For 2-byte integers the conversion is unsigned short SwapBytes (unsigned short source) { unsigned short destination ; destination = ((source & 0xFF) << 8) | ((source & 0xFF00) >> 8) ; return source ; } and 4-byte integers are converted as
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Byte and Bit Ordering unsigned long SwapBytes (unsigned long source) { unsigned long destination ; destination = ((source & 0X000000FFL) << 24) | ((source & 0X0000FF00L) << 8) | ((source & 0X00FF0000L) >> 8) | ((source & 0xFF000000L) >> 24) ; return destination ; } In these programming examples we assume that long is 32 bits and short is 16 bits This is correct for most environments, but not for all
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Whatever the processor type, when processing an entire byte the ordering of bits within a byte is the same However, the ordering of bit strings within individual bytes is a more subtle issue Computer processors deal only with complete bytes When processing compressed data one frequently has to process bit strings that are not aligned on byte boundaries Bit strings can be extracted from bytes, but their ordering is determined entirely by the image format Suppose that you need to read three 3-bit strings from the 2-byte sequence 1st Byte 0 0 0 1 1 1 0 1 2nd Byte 0 1 1 0 0 0 1 1 Depending upon whether the bit strings are read from the most significant bit to least significant bit and whether the bits in the second byte are made the most significant or least significant, the resulting bit strings could be one of these four possibilities:
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The ordering of bit strings within bytes is specified by the image format Except for XBM, in all image file formats in this book that support images with fewer than 8 bits per pixel, the most significant bits within a byte contain the values of the leftmost pixel One should view the bit ordering in these formats as Data Byte |7 6 5 4|3 2 1 0| 4 bits per pixel |7 6|5 4|3 2 | 1 0| 2 bits per pixel | 7 | 6 | 5 | 4 | 3 | 2 | 1 | 0 | 1 bit per pixel Leftmost Pixel Rightmost Pixel
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