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APPENDIX D
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(a) First, the expression ++i is evaluated, resulting in the value 2 Now the variable i also has the value 2 The target of the assignment is now determined to be the element array[2] Evaluation of the right-hand expression, --i, results in the value 1 The variable i now has the value 1 The value of the right-hand expression 1 is then assigned to the array element array[2], resulting in the array contents to become {4, 8, 1} The program sums these values and prints 13
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(a) and (c) The expression (4 <= 4) is true The null literal can be compared, so (null != null) yields false
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(c) and (e) The remainder operator is not limited to integral values, but can also be applied to floating-point operands Short-circuit evaluation occurs with the conditional operators (&&, ||) The operators *, /, and % have the same level of precedence The type short has the range -32768 to +32767, inclusive (+15) is a legal expression using the unary + operator
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(a), (c), and (e) The != and ^ operators, when used on boolean operands, will return true if and only if one operand is true, and false otherwise This means that d and e in the program will always be assigned the same value, given any combination of truth values in a and b The program will, therefore, print true four times
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(b) The element referenced by a[i] is determined based on the current value of i, which is zero, ie, the element a[0] The expression i = 9 will evaluate to the value 9, which will be assigned to the variable i The value 9 is also assigned to the array element a[0] After the execution of the statement, the variable i will contain the value 9, and the array a will contain the values 9 and 6 The program will print 9 9 6, when run
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(c) and (d) Unlike the & and | operators, the && and || operators short-circuit the evaluation of their operands if the result of the operation can be determined from the value of the first operand The second operand of the || operator in the program is never evaluated because of short-circuiting All the operands of the other operators are evaluated Variable i ends up with the value 3, which is the first digit printed, and j ends up with the value 1, which is the second digit printed
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APPENDIX D
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6 Control Flow
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61 (d) The program will display the letter b when run The second if statement is evaluated since the boolean expression of the first if statement is true The else clause belongs to the second if statement Since the boolean expression of the second if statement is false, the if block is skipped and the else clause is executed 62 (a), (b), and (e) The conditional expression of an if statement can have any subexpressions, including method calls, as long as the whole expression evaluates to a value of type boolean The expression (a = b) does not compare the variables a and b, but assigns the value of b to the variable a The result of the expression is the value being assigned Since a and b are boolean variables, the value returned by the expression is also boolean This allows the expression to be used as the condition for an if statement An if statement must always have an if block, but the else clause is optional The expression if (false) ; else ; is legal In this case, both the if block and the else block are simply the empty statement 63 (f) There is nothing wrong with the code The case and default labels do not have to be specified in any specific order The use of the break statement is not mandatory, and without it the control flow will simply fall through the labels of the switch statement 64 (a) and (f) The type of the switch expression must be either an enum type or one of the following: byte, char, short, int or the corresponding wrapper type for these primitive types This excludes (b) and (e) The type of the case labels must be assignable to the type of the switch expression This excludes (c) and (d) The case label value must be a constant expression, which is not the case in (g) where the case label value is of type Byte 65 (c) The case label value 2 * iLoc is a constant expression whose value is 6, the same as the switch expression Fall through results in the printout shown in (c) 66 (b) The switch expression, when unboxed, has the value 5 The statement associated with the default label is excecuted, and the fall through is stopped by the break statement
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