1510: THE SortedMap<K,V> AND NavigableMap<K,V> INTERFACES in Java

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1510: THE SortedMap<K,V> AND NavigableMap<K,V> INTERFACES
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(c) int frequency = freqMapget(key);
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frequency = (frequency == 0) 1 : frequency+1; freqMapput(key, frequency);
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(d) Integer frequency = (!freqMapcontainsKey(key)) 1 : freqMapget(key)+1;
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freqMapput(key, frequency);
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What will the program print when compiled and run
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import import import import javautilCollection; javautilMap; javautilNavigableMap; javautilTreeMap;
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public class MapModify { public static void main(String[] args) NavigableMap<String, Integer> grades gradesput("A", 5); gradesput("B", gradesput("D", 20); gradesput("E",
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{ = new TreeMap<String, Integer>(); 10); gradesput("C", 15); 25);
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Systemoutprintf("1:%d, ", gradesget(gradesfirstKey())); Systemoutprintf("2:%d, ", sumValues(gradesheadMap("D"))); Systemoutprintf("3:%d, ", sumValues(gradessubMap("B", false, "D", true))); gradessubMap(gradesfirstKey(), false, gradeslastKey(), false)clear(); Systemoutprintf("4:%d%n", sumValues(grades)); } public static <K, M extends Map<K, Integer>> int sumValues(M freqMap) { Collection<Integer> values = freqMapvalues(); int sumValues= 0; for (int value : values) sumValues += value; return sumValues; } }
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Select the one correct answer (a) 1:5, 2:50, 3:35, 4:30 (b) 1:5, 2:30, 3:35, 4:30 (c) 1:5, 2:30, 3:25, 4:30 (d) 1:5, 2:30, 3:35, 4:75 1534 Which code, when inserted independently at (1), will result in the following output from the program: {Soap=10, Salts=10}
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import javautil*; public class Mapping { public static void main(String[] args) { NavigableMap<String, Integer> myMap = new TreeMap<String, Integer>(CollectionsreverseOrder()); myMapput("Soap", 10); myMapput("Shampoo", 5); myMapput("Salts", 10); // (1) INSERT CODE HERE Systemoutprintln(myMap); } }
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CHAPTER 15: COLLECTIONS AND MAPS
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Select the two correct answers (a) for (MapEntry<String, Integer> entry : myMapentrySet())
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if (entrygetKey()equals("Shampoo")) myMapremove("Shampoo");
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(b) for (Iterator<String> iterator = myMapkeySet()iterator();
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iteratorhasNext();) if (iteratornext()equals("Shampoo")) iteratorremove();
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(c) for (Iterator<String> iterator = myMapkeySet()iterator();
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iteratorhasNext();) { if (iteratornext()equals("Shampoo")) myMapremove("Shampoo");
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(d) for (MapEntry<String, Integer> entry : myMapentrySet())
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if (entrygetKey()equals("Shampoo")) myMapremove(entry);
(e) myMapsubMap("Shampoo", true, "Shampoo", true)clear(); 1535 Which code, when inserted independently at (1), will result in the following output from the program: {1=Odd, 2=Even, 3=Odd}
import javautilMap; import javautilTreeMap; public class StringBuilderMap { public static void main(String[] args) { Map<Integer, StringBuilder> myMap = new TreeMap<Integer, StringBuilder>(); for (Integer key : new int[] {1, 2, 1, 3, 1, 2, 3, 3}) { // (1) INSERT CODE HERE } Systemoutprintln(myMap); } private static StringBuilder toggle(StringBuilder strBuilder) { String value = "Odd"; if (strBuildertoString()equals(value)) value = "Even"; return strBuilderreplace(0, strBuilderlength(), value); } }
Select the one correct answer (a) StringBuilder value = myMapget(key);
myMapput(key, (value == null) new StringBuilder("Odd") : StringBuilderMaptoggle(value));
(b) StringBuilder value = myMapget(key);
if (value == null) value = new StringBuilder("Odd"); else StringBuilderMaptoggle(value); myMapput(key, value);
1510: THE SortedMap<K,V> AND NavigableMap<K,V> INTERFACES
(c) StringBuilder value = myMapget(key);
if (!myMapcontainsKey(key)) myMapput(key, new StringBuilder("Odd")); else StringBuilderMaptoggle(value);
(d) All of the above 1536 Which code, when inserted independently at (1), will result in the following output from the program: {1=Odd, 2=Even, 3=Odd}
import javautilMap; import javautilTreeMap; public class StringMap { public static void main(String[] args) { Map<Integer, String> myMap = new TreeMap<Integer, String>(); for (Integer key : new int[] {1, 2, 1, 3, 1, 2, 3, 3}) { // (1) INSERT CODE HERE } Systemoutprintln(myMap); } private static String toggle(String str) { if (strequals("Odd")) str = strreplace("Odd", "Even"); else str = strreplace("Even", "Odd"); return str; } }
Select the one correct answer (a) String value = myMapget(key);
myMapput(key, (value == null) "Odd" : StringMaptoggle(value));
(b) String value = myMapget(key);
if (value == null) value = "Odd"; else StringMaptoggle(value); myMapput(key, value);
(c) String value = myMapget(key);
if (!myMapcontainsKey(key)) myMapput(key, "Odd"); else StringMaptoggle(value);
(d) All of the above
CHAPTER 15: COLLECTIONS AND MAPS
1511 Working with Collections
The Java Collections Framework also contains two classes, Collections and Arrays, that provide various operations on collections and arrays, such as sorting and searching, or creating customized collections Practically any operation on a list can be done using the methods covered in this section The methods provided are all public and static, therefore these two keywords will be omitted in their method header declarations in this section The methods also throw a NullPointerException if the specified collection or array references passed to them are null
Ordering Elements in Lists
The Collections class provides two static methods for sorting lists
<E extends Comparable< super E>> void sort(List<E> list) <E> void sort(List<E> list, Comparator< super E> c)
The first method sorts the elements in the list according to their natural ordering The second method does the sorting according to the total ordering defined by the comparator In addition, all elements in the list must be mutually comparable: the method call e1compareTo(e2) (or e1compare(e2) in case of the comparator) must not throw a ClassCastException for any elements e1 and e2 in the list In other words, it should be possible to compare any two elements in the list Note that the second method does not require that the type parameter E is Comparable
<E> Comparator<E> reverseOrder() <E> Comparator<E> reverseOrder(Comparator<E> comparator)
The first method returns a comparator that enforces the reverse of the natural ordering The second one reverses the total ordering defined by the comparator Both are useful for maintaining objects in reverse-natural or reverse-total ordering in sorted collections and arrays This code shows how a list of strings is sorted according to different criteria
List<String> strList = new ArrayList<String>(); strListadd("biggest"); strListadd("big"); strListadd("bigger"); strListadd("Bigfoot"); Collectionssort(strList); // Natural order Collectionssort(strList, CollectionsreverseOrder()); // Reverse natural order Collectionssort(strList, StringCASE_INSENSITIVE_ORDER);// Case insensitive order Collectionssort(strList, // Reverse case insensitive order CollectionsreverseOrder(StringCASE_INSENSITIVE_ORDER));
The output below shows the list before sorting, followed by the results from the calls to the sort() methods above, respectively:
1511: WORKING WITH COLLECTIONS Before sorting: After sorting in After sorting in After sorting in After sorting in
839 [biggest, big, bigger, Bigfoot] [Bigfoot, big, bigger, biggest] [biggest, bigger, big, Bigfoot] [big, Bigfoot, bigger, biggest] [biggest, bigger, Bigfoot, big]
natural order: reverse natural order: case insensitive order: reverse case insensitive order:
It is important to note that the element type of the list must implement the Comparable interface, otherwise the compiler will report an error The following code shows that a list of StringBuilders cannot be sorted because the class StringBuilder does not implement the Comparable interface
List<StringBuilder> sbList = new ArrayList<StringBuilder>(); sbListadd(new StringBuilder("smallest")); sbListadd(new StringBuilder("small")); sbListadd(new StringBuilder("smaller")); Collectionssort(sbList); // Compile-time error!
Below is an example of a list whose elements are not mutually comparable Raw types are used intentionally to create such a list Predictably the sort() method throws an exception because the primitive wrapper classes do not permit interclass comparison
List freakList = new ArrayList(); // Raw types freakListadd(23); freakListadd(314); freakListadd(10L); Collectionssort(freakList); // ClassCastException
The comparator returned by the reverseOrder() method can be used with sorted collections The elements in the following sorted set would be maintained in descending order:
Set<Integer> intSet = new TreeSet<Integer>(CollectionsreverseOrder()); intSetadd(9); intSetadd(11); intSetadd(-4); intSetadd(1); Systemoutprintln(intSet); // [11, 9, 1, -4]
The following utility methods apply to any list, regardless of whether the elements are Comparable or not:
void reverse(List< > list)