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16 If A is in s, then sfind( A ) returns an iterator located at the element A If A is not in s, then sfind( A ) returns send( ) 17 Just note that aN + b (a + b)N, as long as 1 N 18 This is mathematics, not C++ So, = will mean equals, not assignment First note that loga N = (loga b)(logb N) To see this rst identity just note that if you raise a to the power loga N you get N and if you raise a to the power (loga b)(logb N) you also get N If you set c = (loga b) you get loga N = c(logb N) 19 The programs should run exactly the same 20 #include <iostream>
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#include <vector> #include <algorithm> using std::cout; using std::vector; using std::vector<int>::const_iterator; using std::search; vector<int> target; targetpush_back(42); targetpush_back(43); const_iterator result = search(vbegin( ), vend( ), targetbegin( ), targetend( )); if (result != vend( )) cout << "Found 42, 43\n"; else cout << "42, 43 not there\n";
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21 No, you must have random-access iterators, and the list template class only has bidirectional iterators 22 Yes, a random-access iterator is also a forward iterator 23 The set_union template function requires that the containers keep their elements in sorted order to allow the function template to be implemented in a more efficient way
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1 The point of this exercise is to demonstrate that: An object that behaves like an iterator is an iterator More precisely, if an object accesses some container and behaves like an iterator of a particular strength, then that object can be used as an iterator to manipulate the container with any of the generic functions that require an iterator having that strength However, while the generic algorithms can be used with this container, the member functions, such as begin and end, will (of course) not be present (for example, in an array) unless they have
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been explicitly coded for that container We will restrict this exercises to arrays of double, but the same message would hold true for any base type a Argue from the properties of random access iterators that a pointer that points to an element of an array behaves exactly as a random access iterator b Argue further that i) the name of the array is a pointer to double that points to the rst element and so the array name can serve as a begin iterator and ii) that (the array's name) + (the size of the array) can serve as an end pointer (Of course, this points one past the end, as it should) c Write a short program in which you declare an array of double of size 10, populate this array with 10 doubles Then call the sort generic algorithm with these pointer values as arguments and display the results 2 This problem intends to illustrate removal of several instances of a particular item from a container with the remove generic function A side effect is to examine the behavior of the generic function remove that comes with your compiler (We have observed some variation in the behavior of remove from one compiler to another) Before you start, look up the behavior of the remove generic algorithm as described by your favorite STL document or web site (For example, point your browser at wwwsgicom, click the fast find down arrow, click STL, click index, scroll down to and click remove This worked as of the publication date) a Modify the array declaration in Programming Project 1 to include several elements with the same value (say, 40, but you can use any value for this exercise) Make sure that some of these are not all together Use the modifying generic function remove (see Display 1918) to remove all elements 40 (that is, the value you duplicated in building the array) Test b Use the array of double from part a) to build a list and a vector that have the same contents as the array Do this using the container constructor that takes two iterators as arguments The vector and list classes each have a constructor that takes two iterators as arguments and initializes the vector or list to the items in the iterator interval The iterators can be located in any container, including in an array Build the vector and list using the array name for the begin iterator and the name + array length as the end iterator for the two constructor arguments Use the modifying algorithm remove (Display 1918) to remove from the list and from the vector all elements equal to 40 (or the value you duplicated in building the array) Display the contents of the vector and list and explain the results c Modify the code from part b) to assign to an iterator variable of appropriate type the iterator value returned by the call to the remove generic function Review the documentation for remove to be certain you know what these iterator values mean Output the contents of the array, the vector and the list, begin() to end(), using the begin and end we described above for the array Output the contents of the two containers starting at the iterator retuned from remove to the end() of each container Explain your results
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